A) \[{{(3/4)}^{50}}\]
B) \[{{(2/7)}^{50}}\]
C) \[{{(1/8)}^{50}}\]
D) \[{{(7/8)}^{50}}\]
Correct Answer: A
Solution :
[a] For each toss, there are four choices:| (i) A gets head, B gets head |
| (ii) A gets tail, B gets head |
| (iii) A gets head, B gets tail |
| (iv) A gets tail, B gets tail Thus, exhaustive number of ways is\[{{4}^{50}}\]. Out of the four choices listed above, (iv) is not favorable to the required event in a toss. Therefore, favorable number of cases is\[{{3}^{50}}\]. Hence, the required probability is\[{{(3/4)}^{50}}\]. |
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