A) \[p=\sqrt{11}-3\]
B) \[\sqrt{10}-3\]
C) \[\frac{1}{4}<p<\frac{1}{2}\]
D) none
Correct Answer: A
Solution :
[a] \[{{p}^{2}}+2p+4p-1=1\] (Exhaustive) \[{{p}^{2}}+6p-2=0\] Or \[p=-3\pm \sqrt{11}=\sqrt{11}-3\]
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