A) \[1/780\]
B) \[40!/{{2}^{780}}\]
C) \[40!/{{3}^{780}}\]
D) none of these
Correct Answer: B
Solution :
[b] Team totals must be 0, 1, 2,?39, Let the teams be \[{{T}_{1}}{{T}_{2}},...,{{T}_{40}},\] so that \[{{T}_{1}}\] loses to \[{{T}_{1}}\] for \[i<j\]. in other words, this order uniquely determines the result of every game. There are 40! Such orders and 780 games, so \[{{2}^{780}}\] possible outcomes for the games, Hence, the probability is\[40!/{{2}^{780}}\].
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