A) 4/625
B) 18/625
C) 16/625
D) none of these
Correct Answer: C
Solution :
[c] The total number of digits in any number at the unit's place is 10. Therefore, \[n(S)=10\] If the last digit in product is 1, 3, 5 or 7, then it is necessary that the last digit in each number must be 1, 3, 5 or 7. Therefore. \[n(A)=4\] \[\therefore P(A)=\frac{4}{10}=\frac{2}{5}\] Hence, the required probability is \[{{(2/5)}^{4}}=16/625.\]
You need to login to perform this action.
You will be redirected in
3 sec
