A) 2/19
B) 7/20
C) \[1-{{(7/20)}^{3}}\]
D) none of these
Correct Answer: D
Solution :
[d] Let X denote the largest number on the 3 tickets drawn. Then, \[P(X\le 7)={{(7/20)}^{3}}\] and \[P(X\le 6)={{(6/20)}^{3}}.\] Then, the required probability is \[P(X=7)={{\left( \frac{7}{20} \right)}^{3}}-{{\left( \frac{6}{20} \right)}^{3}}\]
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