A) \[N{{H}_{4}}N{{O}_{3}}\]
B) \[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\]
C) \[{{(N{{H}_{4}})}_{2}}C{{O}_{3}}\]
D) \[NaCl\]
Correct Answer: A
Solution :
[a] As it provides \[N{{H}^{+}}_{4}\]ions which suppresses the ionization of \[N{{H}_{4}}OH\]so that only the group III cations are precipitated as hydroxides because of their low solubility products and \[N{{O}^{-}}_{3}\]ions do not produce precipitate with the cations of IVth, Vth and VIth groups.
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