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JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Mock Test - Principles Related to Practical Chemistry

  • question_answer
    A gas "X" is passed through water to form a saturated solution. The aqueous solution on treatment with silver nitrate gives a white precipitate. The saturated aqueous solution also dissolves magnesium ribbon with evolution of a colorless gas "Y". Identify X and Y.

    A) \[X=C{{O}_{2}}\], \[Y=C{{l}_{2}}\]

    B) \[X=C{{l}_{2}}\], \[Y=C{{O}_{2}}\]

    C) \[X=C{{l}_{2}}\], \[Y={{H}_{2}}\]

    D) \[X={{H}_{2}}\], \[Y=C{{l}_{2}}\]

    Correct Answer: C

    Solution :

    [c] \[\underset{(X)}{\mathop{C{{l}_{2}}}}\,+{{H}_{2}}O\to HOCl+HCl\] \[AgN{{O}_{3}}+HCl\to \underset{white\,ppt}{\mathop{AgCl}}\,+HN{{O}_{3}}\] \[Mg+2HCl\to MgC{{l}_{2}}+\underset{(Y)}{\mathop{{{H}_{2}}}}\,\uparrow \]


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