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JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Mock Test - Principles Related to Practical Chemistry

  • question_answer
    Nitrates form a brown ring when treated with \[HCl/FeS{{O}_{4}}\] followed by a few drops of cone. \[{{H}_{2}}S{{O}_{4}}\]. This test depends upon

    A) the reduction of nitrate to nitric oxide

    B) the oxidation of nitric oxide to nitrogen dioxide

    C) reduction of ferrous sulphate to iron

    D) oxidizing action of sulphuric acid

    Correct Answer: A

    Solution :

    [a] Reduction of nitrate by \[F{{e}^{2+}}\]ions. \[N{{O}^{-}}_{3}+3F{{e}^{2+}}+4{{H}^{+}}\to \underset{\begin{smallmatrix}  Nitric \\  oxide \end{smallmatrix}}{\mathop{NO}}\,+3F{{e}^{3+}}+2{{H}_{2}}O\] \[F{{e}^{2+}}+NO+5{{H}_{2}}O\to {{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}\]


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