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JEE Main & Advanced Chemistry Polymers / बहुलक Question Bank Mock Test - Polymers

  • question_answer
    Formation of polyethylene from calcium carbide takes place as follows: \[Ca{{C}_{2}}+2{{H}_{2}}O\to Ca{{(OH)}_{2}}+{{C}_{2}}{{H}_{2}}\]\[{{C}_{2}}{{H}_{2}}+{{H}_{2}}\to {{C}_{2}}{{H}_{2}}\] \[n{{C}_{2}}{{H}_{2}}\to {{(-C{{H}_{2}}-C{{H}_{2}}-)}_{n}}\] The amount of polyethylene obtained from 64.1 kg of\[Ca{{C}_{2}}\] is

    A) 7 kg                 

    B) 4 kg

    C) 21 kg    

    D) 28 kg

    Correct Answer: B

    Solution :

    [d] \[Ca{{C}_{2}}(64kg)\] will produce 28 kg of\[{{(-C{{H}_{2}}-C{{H}_{2}}-)}_{n}}\].


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