JEE Main & Advanced
Chemistry
Polymers / बहुलक
Question Bank
Mock Test - Polymers
question_answer
Formation of polyethylene from calcium carbide takes place as follows: \[Ca{{C}_{2}}+2{{H}_{2}}O\to Ca{{(OH)}_{2}}+{{C}_{2}}{{H}_{2}}\]\[{{C}_{2}}{{H}_{2}}+{{H}_{2}}\to {{C}_{2}}{{H}_{2}}\] \[n{{C}_{2}}{{H}_{2}}\to {{(-C{{H}_{2}}-C{{H}_{2}}-)}_{n}}\] The amount of polyethylene obtained from 64.1 kg of\[Ca{{C}_{2}}\] is
A)7 kg
B)4 kg
C)21 kg
D)28 kg
Correct Answer:
B
Solution :
[d] \[Ca{{C}_{2}}(64kg)\] will produce 28 kg of\[{{(-C{{H}_{2}}-C{{H}_{2}}-)}_{n}}\].