A) 0.4 Ns
B) 0.8 Ns
C) 1.6Ns
D) 0.2 Ns
Correct Answer: B
Solution :
[b] From the graph, it can be seen that it is a straight line, so the motion is uniform. Because of impulse, the direction of velocity changes as can be seen form the slope of the graph. Initial velocity \[=\frac{2}{2}=1m/s\] Final velocity \[=-\frac{2}{2}=-1m/s\] \[{{\vec{P}}_{i}}=0.4N-s\] \[{{\vec{P}}_{f}}=-0.4N-s\] \[\vec{J}={{\vec{P}}_{f}}-{{\vec{P}}_{i}}=-0.4=0.8N-s\](\[\vec{J}\]=impluse) \[\left| {\vec{J}} \right|\]=0.8N-s
You need to login to perform this action.
You will be redirected in
3 sec
