A) 8 : 1
B) 9 : 7
C) 4 : 3
D) 5 : 3
Correct Answer: B
Solution :
[b] From F.B.D. of \[{{m}_{1}}:T-{{m}_{1}}g={{m}_{1}}a\] (i) From F.B.D. of \[{{m}_{2}}:{{m}_{2}}g-T={{m}_{2}}a\] (ii) From (i) and (ii), \[a=\left( \frac{{{m}_{2}}-{{m}_{1}}}{{{m}_{1}}+{{m}_{2}}} \right)g\] \[\Rightarrow \frac{g}{8}=\left( \frac{{{m}_{2}}-{{m}_{1}}}{{{m}_{1}}+{{m}_{2}}} \right)g\Rightarrow \frac{{{m}_{2}}}{{{m}_{1}}}=\frac{9}{7}\]You need to login to perform this action.
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