JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Mock Test - Newtons Laws of Motion without Friction

  • question_answer
    A wooden box is placed on a table. The normal force on the box from the table is A \[{{N}_{1}}\]. Now another identical box is kept on first box and the normal force on lower block due to upper block is A\[{{N}_{2}}\] and normal force on lower block by the table is \[{{N}_{3}}\]. For this situation, mark out the correct statement(s).

    A)  \[{{N}_{1}}={{N}_{2}}={{N}_{3}}\]

    B) \[{{N}_{1}}<{{N}_{2}}={{N}_{3}}\]

    C) \[{{N}_{1}}={{N}_{2}}>{{N}_{3}}\]

    D)  None of these

    Correct Answer: D

    Solution :

    [d] Let the weight of each block be W (see figure) So, \[{{N}_{1}}={{N}_{2}}=\frac{{{N}_{3}}}{2}\]


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