A) \[\frac{{{M}_{2}}-{{M}_{1}}}{\mu }\]
B) \[\frac{{{M}_{2}}}{\mu }-{{M}_{1}}\]
C) \[{{M}_{2}}\,\frac{{{M}_{1}}}{\mu }\]
D) \[\,\,({{M}_{2}}\,-{{M}_{1}})\mu \]
Correct Answer: B
Solution :
[b] For the equilibrium of block of mass \[{{M}_{1}}:\] Frictional force, f=tension in the string, T Where \[T=f=\mu (m+{{M}_{1}})g\] For the equilibrium of block of mass \[{{M}_{2}}:\] \[T={{M}_{2}}g\] From Eqs. (i) and (ii), we get\[\mu (m+{{M}_{1}})g={{M}_{2}}g\] \[m=\frac{{{M}_{2}}}{\mu }-{{M}_{1}}\]
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