A) \[8{}^\circ \]
B) \[~45{}^\circ \]
C) \[37{}^\circ \]
D) \[30{}^\circ \]
Correct Answer: C
Solution :
[c] As sand particles are sliding down, the slope of the hill gets reduced. The sand particle stops coming down when component of gravity force along the hill is balanced by limiting friction force. \[mg\sin \theta ={{\mu }_{s}}mg\cos \theta \] \[\Rightarrow \theta ={{\tan }^{-1}}({{\mu }_{s}})\simeq 37{}^\circ \] Where \[\theta \]is the new slope angle of hill.
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