A) \[{{t}_{1}}={{t}_{2}}\]
B) \[{{t}_{1}}>{{t}_{2}}\]
C) \[{{t}_{2}}>{{t}_{1}}\]
D) \[{{t}_{1}}=2{{t}_{2}}\]
Correct Answer: C
Solution :
[c] The retardation r of the block while moving up is \[g(sin\theta +\mu cos\theta )\]while the acceleration a of the block while moving down is \[g(sin\theta -\mu \cos \theta )\] \[{{t}_{1}}\propto \frac{1}{\sqrt{r}}\]and \[{{t}_{2}}\propto \frac{1}{\sqrt{a}}\]since \[r=a,{{t}_{2}}>{{t}_{1}}\]
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