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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Mock Test - Motion in Two Dimension

  • question_answer
    A particle is moving on a circular path of radius r with uniform velocity v. The change in velocity when the particle moves from \[P\] to \[Q\] is \[(\angle POQ={{40}^{{}^\circ }})\]

    A) \[2v\,\cos \,40{}^\circ \]

    B) \[2v\,\sin 40{}^\circ \]

    C) \[2v\,\sin \,20{}^\circ \]

    D) \[2v\,\cos \,20{}^\circ \]

    Correct Answer: C

    Solution :

    [c] Change in velocity =\[2v\sin (\theta /2)=2vsin20{}^\circ \]  


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