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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Mock Test - Motion in Two Dimension

  • question_answer
    An aircraft moving with a speed of 1000 km/h is at a height of 6000 m, just overhead of an anti-aircraft gun. If the muzzle velocity of the gun is 540 m/s, the firing angle \[\theta \] for the bullet to hit the aircraft should be

    A) \[73{}^\circ \]             

    B) \[30{}^\circ \]

    C) \[60{}^\circ \] 

    D) \[45{}^\circ \]

    Correct Answer: C

    Solution :

    [c] Displacement of aircraft in time t=horizontal displacement of projectile \[\Rightarrow 972\times \frac{5}{18}t={{V}_{0}}\cos \theta .t\] \[\Rightarrow \cos \theta =\frac{54\times 5}{540}=\frac{1}{2}\Rightarrow \theta =60{}^\circ \]                  


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