A) \[6\,km/hr\], inclined at an angle of \[45{}^\circ \] to the vertical towards the person's motion.
B) \[3\,km/hr\], inclined at an angle of \[30{}^\circ \] to the vertical towards the person's motion.
C) \[6\,km/hr\], inclined at an angle of \[30{}^\circ \] to the vertical towards the person's motion.
D) \[6\,km/hr\], inclined at an angle of \[60{}^\circ \] to the vertical towards the person's motion.
Correct Answer: C
Solution :
[c] \[{{\vec{v}}_{r/m}}={{\vec{v}}_{r}}-{{\vec{v}}_{m}}\] \[{{\vec{v}}_{r}}={{\vec{v}}_{r/m}}+{{\vec{v}}_{m}}\] \[\left| {{{\vec{v}}}_{r}} \right|=\sqrt{v_{r/m}^{2}+v_{m}^{2}}\] \[=\sqrt{{{(3)}^{2}}+{{(3\sqrt{3})}^{2}}}=6km/hr\] \[\tan \theta =\frac{3}{3\sqrt{3}}=\frac{1}{\sqrt{3}}\Rightarrow \theta =30{}^\circ \]You need to login to perform this action.
You will be redirected in
3 sec