JEE Main & Advanced Mathematics Determinants & Matrices Question Bank Mock Test - Matrices

  • question_answer
    \[{{(-A)}^{-1}}\] is always equal to (where A is nth-order square matrix)

    A)  \[{{(-1)}^{n}}{{A}^{-1}}\]

    B)  \[-{{A}^{-1}}\]

    C)  \[{{(-1)}^{n-1}}{{A}^{-1}}\]

    D)  none of these

    Correct Answer: B

    Solution :

    [b] \[{{(-A)}^{-1}}=\frac{adj(-A)}{\left| -A \right|}=\frac{{{(-1)}^{n-1}}adj(A)}{{{(-1)}^{n}}\left| A \right|}\] \[=\frac{adj(A)}{-\left| A \right|}=-{{A}^{-1}}\]


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