JEE Main & Advanced Mathematics Linear Programming Question Bank Mock Test - Linear Inequalities

  • question_answer
    The solution set of \[\frac{5x+8}{4-x}\le 2\]is

    A) \[(4,\,\infty )\cup \left( -\infty ,\,0 \right]\]

    B) \[[4,\,\infty ]\cup \left( -\infty ,\,4 \right]\]

    C) \[\left( -\infty ,\,0 \right]\cup (4,\,\infty )\]

    D) \[[4,\,\infty ]\cup \left( -\infty ,\,0 \right]\]

    Correct Answer: C

    Solution :

    [c] \[\frac{5x+8}{4-x}\le 2\Rightarrow \frac{5x+8}{4-x}-2\le 0\] \[\Rightarrow \frac{5x+8-8+2x}{4-x}\le 0\] \[\Rightarrow \frac{7x}{4-x}\le 0\Rightarrow \frac{x-0}{x-4}\ge 0\] Dividing by -7 \[\Rightarrow (-\infty ,0]\cup (4,\infty )\]


You need to login to perform this action.
You will be redirected in 3 sec spinner