A) \[{{e}^{4}}\]
B) \[{{e}^{2}}\]
C) \[{{e}^{3}}\]
D) 1
Correct Answer: D
Solution :
[d] \[\underset{x\to \infty }{\mathop{\lim }}\,-{{\left( \frac{{{x}^{2}}+5x+3}{{{x}^{2}}+x+3} \right)}^{1/x}}=\underset{x\to \infty }{\mathop{\lim }}\,{{\left( \frac{1+\frac{5}{x}+\frac{3}{{{x}^{2}}}}{1+\frac{1}{x}+\frac{3}{{{x}^{3}}}} \right)}^{1/x}}={{1}^{o}}=1\]
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