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JEE Main & Advanced Physics Kinetic Theory of Gases Question Bank Mock Test - Kinetic Theory of Gases and Laws of Thermodynamics

  • question_answer
    A thermodynamic process is shown in figure. The pressures and volumes corresponding to some points in the figure are:\[{{P}_{A}}=3\times {{10}^{4}}Pa,\,\,{{P}_{B}}=8\times {{10}^{4}}Pa\]\[and\,{{V}_{A}}=2\times {{10}^{-3}}{{m}^{3}},\,{{V}_{D}}=5\times {{10}^{-3}}m\] In process\[AB\], 600 J of heat is added to the system and in process\[BC\], 200 J of heat is added to the system. The change in internal energy of the system in process AC would be

    A) 560 J   

    B) 800 J

    C) 600 J  

    D) 640 J

    Correct Answer: A

    Solution :

    [a] By the graph, \[{{W}_{AB}}=0\]and \[{{W}_{BC}}=8\times {{10}^{4}}[5-2]\times {{10}^{-3}}=240J\] \[\therefore {{W}_{AC}}={{W}_{AB}}+{{W}_{BC}}=0+240=240J\]Now, \[{{Q}_{AC}}={{Q}_{AB}}+{{Q}_{BC}}=600+200=800J\] From the first law of thermodynamics, \[{{Q}_{AC}}=\Delta {{U}_{AC}}+{{W}_{AC}}\] \[\Rightarrow 800=\Delta {{U}_{AC}}+240\]or \[\Delta {{U}_{AC}}=560J\]


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