A) \[6.60\times {{10}^{-23}}g\]
B) \[3.30\times {{10}^{-23}}g\]
C) \[2.20\times {{10}^{-23}}g\]
D) \[13.20\times {{10}^{-23}}g\]
Correct Answer: A
Solution :
[a] Molar specific heat = molecular weight \[\times \]gram specific heat \[{{C}_{v}}=M\times {{c}_{v}}\] \[2.98\,cal/mol-K=M\times 0.075Kcal/kg-K\] \[=M\times \frac{0.075\times {{10}^{3}}}{{{10}^{3}}}cal/g-K\] \[\therefore \]Molecular weight of argon \[M=\frac{2.98}{0.075}=39.7g\] i.e., mass of \[6.023\times {{10}^{23}}\]atom = 39.7 g Therefore, mass of single atom \[=\frac{39.7}{6.023\times {{10}^{23}}}=6.60\times {{10}^{-23}}g\]
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