A) 2
B) 10
C) 4
D) 5
Correct Answer: D
Solution :
[d] From Dalton's law, final pressure of the mixture of nitrogen and oxygen is \[P={{P}_{1}}+{{P}_{2}}\] \[=\frac{{{\mu }_{1}}RT}{V}+\frac{{{\mu }_{2}}RT}{V}=\frac{{{m}_{1}}}{{{M}_{1}}}\frac{RT}{V}+\frac{{{m}_{2}}}{{{V}_{2}}}\frac{RT}{V}\] \[=\frac{8}{32}\frac{RT}{V}+\frac{7}{28}\frac{RT}{V}=\frac{RT}{2V}\Rightarrow 10=\frac{RT}{2V}\] ...(i) When oxygen is absorbed then for nitrogen let pressure is \[P=\frac{7}{28}\frac{RT}{4V}\] \[\Rightarrow P=\frac{RT}{4T}\] ...(ii) From Eqs. (i) and (ii), we get pressure of the nitrogen P=5 atm
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