A) 1:2
B) 1 : 4
C) 1 :5
D) 1 : 10
Correct Answer: D
Solution :
[d] \[{{U}_{1}}=n\left( \frac{5R}{2} \right)T\] \[And\text{ }{{U}_{2}}=\frac{2}{n}\left( \frac{5R}{2} \right)T+\frac{2n}{2}\left( \frac{3R}{2} \right)T=n\left( \frac{11R}{4} \right)T\] \[{{U}_{2}}={{U}_{1}}+Q\] \[\therefore \frac{Q}{{{U}_{1}}}=\frac{{{U}_{2}}}{{{U}_{1}}}-1=\frac{11}{10}-1=\frac{1}{10}\]
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