A) \[80{}^\circ C\], \[37{}^\circ C\]
B) \[95{}^\circ C\], \[98{}^\circ C\]
C) \[90{}^\circ C\], \[37{}^\circ C\]
D) \[99{}^\circ C\], \[37{}^\circ C\]
Correct Answer: D
Solution :
[d] Initially \[\eta =\left( 1-\frac{{{T}_{2}}}{{{T}_{1}}} \right)=\frac{W}{Q}=\frac{1}{6}\] ...(i) Finally \[\eta '=\left( 1-\frac{T{{'}_{2}}}{{{T}_{1}}} \right)=\left( 1-\frac{({{T}_{2}}-62)}{{{T}_{1}}} \right)=1-\frac{{{T}_{2}}}{{{T}_{1}}}+\frac{62}{{{T}_{1}}}\] \[=\eta +\frac{62}{{{T}_{1}}}\] ...(ii) It is given that \[\eta '=2\eta \]hence solving equation (i) and (ii) \[{{T}_{1}}=372K=99{}^\circ C\] and \[{{T}_{2}}=310K=37{}^\circ C\]
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