A) \[3.7\times {{10}^{-3}}M\]
B) \[1.11\times {{10}^{-3}}M\]
C) \[1.11\times {{10}^{-4}}M\]
D) \[3.7\times {{10}^{-4}}M\]
Correct Answer: D
Solution :
[d] \[[{{H}^{+}}]={{10}^{-3}}M,[{{H}^{+}}]={{10}^{-4}}M,[{{H}^{+}}]={{10}^{-5}}M\] for the given acids. \[{{M}_{mix}}{{V}_{mix}}={{M}_{1}}{{V}_{1}}+{{M}_{2}}{{V}_{2}}+{{M}_{3}}{{V}_{3}}\] \[{{M}_{mix}}\times 3={{10}^{-3}}\times 1+{{10}^{-4}}\times 1+{{10}^{-5}}\times 1\] \[{{M}_{mix}}=\frac{{{10}^{-5}}[100+10+1]}{3}=\frac{111\times {{10}^{-5}}}{3}\] \[=37\times {{10}^{-5}}M=3.7\times {{10}^{-4}}M\]
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