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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Mock Test - Ionic Equilibrium

  • question_answer
    The pH of Ba \[{{(OH)}_{2}}\]solution is 13. The number millimoles of Ba\[{{(OH)}_{2}}\] present in 10 ml of solution would be

    A) 1.00                 

    B) 0.50

    C) 10.00  

    D) 15.00

    Correct Answer: B

    Solution :

    [b] \[[O{{H}^{-}}]=0.1\] and conc. Of \[Ba{{(OH)}_{2}}=\frac{0.1}{2}\] \[\therefore \]The no. of millimoles of \[Ba{{(OH)}_{2}}\]present in 10 ml solution \[=\frac{0.1}{2}\times 10\times {{10}^{-3}}\times {{10}^{3}}=0.5\]


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