A) \[1.74\times {{10}^{-5}}\]
B) \[3.52\times {{10}^{-3}}\]
C) \[6.75\times {{10}^{-4}}\]
D) \[5.38\times {{10}^{-2}}\]
Correct Answer: C
Solution :
[c] \[HF+{{H}_{2}}O\rightleftharpoons {{F}^{-}}+{{H}_{3}}{{O}^{+}}\] \[{{K}_{a}}\times {{K}_{b}}={{K}_{w}}\] \[p{{K}_{a}}+p{{K}_{b}}=p{{K}_{w}}\] \[p{{K}_{a}}=14-10.83\Rightarrow p{{K}_{a}}=3.17\] \[{{K}_{a}}=6.75\times {{10}^{-4}}\]
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