A) \[5.0\times {{10}^{-5}}\]
B) \[5.0\times {{10}^{15}}\]
C) \[5.0\times {{10}^{-15}}\]
D) \[0.2\times {{10}^{5}}\]
Correct Answer: C
Solution :
[c] \[{{H}_{2}}A\rightleftharpoons H{{A}^{-}}+{{H}^{+}}\] \[\therefore {{K}_{1}}=1.0\times {{10}^{-5}}=\frac{[{{H}^{+}}][H{{A}^{-}}]}{[{{H}_{2}}A]}\] (given) \[H{{A}^{-}}\to {{H}^{+}}+{{A}^{2-}}\] \[\therefore {{K}_{2}}=5.0\times {{10}^{-10}}=\frac{[{{H}^{+}}][{{A}^{2-}}]}{[{{H}_{2}}A]}\] (given) \[K=\frac{{{[{{H}^{+}}]}^{2}}[{{A}^{2-}}]}{[{{H}_{2}}A]}={{K}_{1}}\times {{K}_{2}}\]
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