JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Mock Test - Ionic Equilibrium

  • question_answer
    In a saturated solution of the sparingly soluble strong electrolyte \[AgI{{O}_{3}}\] (molecular mass = 283) the equilibrium which sets in is \[AgI{{O}_{3}}(s)\rightleftharpoons A{{g}^{+}}(aq)+I{{O}^{-}}_{3}(aq)\] If the solubility product constant \[{{K}_{sp}}\]of\[AgI{{O}_{3}}\], at a given temperature is\[1.0\times {{10}^{-8}}\], what is the mass of, \[AgI{{O}_{3}}\] contained in 100 mL of its saturated solution?

    A) \[28.3\times {{10}^{-2}}g\]     

    B) \[28.3\times {{10}^{-3}}g\]

    C) \[1.0\times {{10}^{-7}}g\]       

    D) \[1.0\times {{10}^{-4}}g\]

    Correct Answer: A

    Solution :

    [a] \[AgI{{O}_{3(s)}}\rightleftharpoons A{{g}^{+}}_{(aq)}+I{{O}_{3(aq)}}^{-}\] Let the solubility of \[AgI{{O}_{3}}\]be S \[{{K}_{sp}}=[A{{g}^{+}}][I{{O}_{3}}^{-}]\] \[{{K}_{sp}}=S\times S\] Or \[S=\sqrt{{{K}_{sp}}}\] \[S=\sqrt{1.0\times {{10}^{-8}}}=1.0\times {{10}^{-4}}mol/litre\] \[=1.0\times {{10}^{-4}}\times 283g/litre\] \[=\frac{1.0\times {{10}^{-4}}\times 283}{1000}\times 100g/100ml\] \[=2.83\times {{10}^{-3}}g/100ml=28.3\times {{10}^{-2}}g\]


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