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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Mock Test - Ionic Equilibrium

  • question_answer
    The pH of a buffer is 6.745. When 0.01 mole of NaOH is added to 1 litre of it, the pH changes to 6.832. Its buffer capacity is

    A) 0.187   

    B) 0.115

    C) 0.076  

    D) 0.896

    Correct Answer: B

    Solution :

    [b] Buffer capacity \[=\frac{No.of\,moles\,of\,base\,added/litere\,of\,buffer}{Change\,in\,pH}\] \[=\frac{0.01}{(6.832-6.745)}=\frac{0.01}{0.087}=0.11\]


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