A) HF and \[HCl{{O}_{4}}\]
B) HF and \[Cl{{O}_{4}}^{-}\]
C) HF and \[{{H}_{2}}{{F}^{+}}\]
D) \[HCl{{O}_{4}}\] and \[{{H}_{2}}{{F}^{+}}\]
Correct Answer: C
Solution :
[c] Conjugate acid base pair differ by a proton (\[{{H}^{+}}\]) \[\underset{(acid)}{\mathop{{{H}_{2}}{{F}^{+}}}}\,\xrightarrow{-{{H}^{+}}}\underset{(base)}{\mathop{HF}}\,\]
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