A) \[x\in R\]
B) \[x>0\]
C) \[x\in [-1,1]\]
D) \[x\in (0,1]\]
Correct Answer: D
Solution :
[d] \[\left( \frac{\pi }{2}-2x \right)=\cos 6x=\left\{ \begin{matrix} \frac{\pi }{2}x>0 \\ \frac{-\pi }{2}x<0 \\ \end{matrix} \right.\] \[{{\sin }^{-1}}x+{{\cos }^{-1}}x=\frac{\pi }{2}\forall x\in [-1,\,\,1]\].You need to login to perform this action.
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