JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Mock Test - Inverse Trigonometric Functions

  • question_answer
    The function \[f(x)={{\tan }^{-1}}(\sin x+\cos x)\] is an increasing function in

    A) \[\left( \frac{\pi }{4},\frac{\pi }{2} \right)\]           

    B) \[\left( -\frac{\pi }{2},\frac{\pi }{4} \right)\]

    C) \[\left( 0,\frac{\pi }{2} \right)\]     

    D) \[\left( -\frac{\pi }{2},\frac{\pi }{2} \right)\]

    Correct Answer: B

    Solution :

    [b] \[f'(x)=\frac{1}{1+{{(\sin x+\cos x)}^{2}}}(\cos x-\sin x)\]  \[f(x)\]is increasing if  \[\cos x-\sin x>0\] Or  \[\cos x>\sin x\] Hence, \[f(x)\]is increasing when \[x\in \left( -\frac{\pi }{2},\frac{\pi }{4} \right)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner