A) \[\frac{1}{\sqrt{3}}\]
B) \[-\frac{1}{\sqrt{3}}\]
C) \[\sqrt{3}\]
D) \[-\frac{\sqrt{3}}{4}\]
Correct Answer: A
Solution :
[a] The given equation is \[3(2ta{{n}^{-1}}x)-4(2ta{{n}^{-1}}x)+2(ta{{n}^{-1}}x)=\pi /3\] \[\therefore 2{{\tan }^{-1}}x=\pi /3\] \[\therefore {{\tan }^{-1}}x=\pi /6\] \[\therefore x=\frac{1}{\sqrt{3}}\]You need to login to perform this action.
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