A) 1.339
B) 7.5
C) 5.0
D) 2.68
Correct Answer: B
Solution :
[b] We know, \[V=5.6\times N\] \[{{N}_{1}}=\frac{10}{5.6};{{N}_{2}}=\frac{15}{5.6};{{N}_{3}}=\frac{20}{5.6}\] \[{{N}_{1}}{{V}_{1}}+{{N}_{2}}{{V}_{2}}+{{N}_{3}}{{V}_{3}}={{N}_{R}}{{V}_{R}}\] \[\frac{10}{5.6}\times \frac{1}{2}+\frac{15}{5.6}\times \frac{1}{2}+\frac{20}{5.6}\times \frac{1}{2}={{N}_{R}}\times 3\] Or \[{{N}_{R}}=1.339\] Or \[V={{N}_{R}}\times 5.6=1.339\times 5.6=7.5\]
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