question_answer

An optically active alkyl bromide X (\[{{C}_{6}}{{H}_{13}}Br\]) upon treatment with ethanolic KOH solution forms two alkenes Y and Z with their molecular formula (\[{{C}_{6}}{{H}_{12}}\]). Y and Z are positional isomers. Z upon treatment with cold, dilute alkaline \[KMn{{O}_{4}}\] solution gives a meso-diol. Hence, X is

A) 2-bromohexane

B) 1-bromo-2, 3-dimethyl butane

C) 3-bromohexane

D) 2-bromo-2, 3-dimethyl butane

Correct Answer: C

Solution :

[c] For meso diol, alkene must be cis symmetrical 3-hexene.