A)
B)
C)
D)
Correct Answer: D
Solution :
[d] \[\begin{align} & C{{H}_{3}}-C{{H}_{2}}-C\equiv C-C{{H}_{3}}\xrightarrow[N{{H}_{3}}]{NaN{{H}_{3}}} \\ & \text{Non-terminal}\,\,\text{alkyne} \\ \end{align}\]\[\begin{align} & C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C\equiv CH \\ & \,\,\,\,\,\,\,\,\,\,\,\,\text{Terminal}\,\,\text{alkyne} \\ \end{align}\]You need to login to perform this action.
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