question_answer

An alkane \[{{C}_{6}}{{H}_{14}}(X)\] can be obtained by reduction of five different alkyl halides \[{{C}_{6}}{{H}_{13}}Cl\] (only structural isomers) with\[ZnC{{H}_{3}}COOH\]. The IUPAC name of X satisfying above condition is

A) hexane

B) 2-methyl pentane

C) 2, 3-dimethyl butane

D) 2, 2-dimethyl butane

Correct Answer: B

Solution :

[b] 2-methyl pentane has five types of hydrogen, therefore, it can be obtained by reduction of five different halides as:

(i)	(ii)
(iii)	(iv)
(v)

All of the above chloroalkanes on reduction with \[Zn/C{{H}_{3}}COOH\]would give the same 2-methyl pentane.