A) \[{{\left[ Au(C{{N}_{4}}) \right]}^{3-}}\] and \[{{\left[ Zn{{(CN)}_{4}} \right]}^{2-}}\]
B) \[{{\left[ Au(C{{N}_{2}}) \right]}^{-}}\] and \[{{\left[ Zn{{(CN)}_{6}} \right]}^{4-}}\]
C) \[{{\left[ Au(C{{N}_{4}}) \right]}^{4-}}\]and \[{{\left[ Zn{{(CN)}_{4}} \right]}^{2}}\]
D) \[{{\left[ Au(C{{N}_{4}}) \right]}^{4-}}\] and \[{{\left[ Zn{{(CN)}_{4}} \right]}^{2-}}\]
Correct Answer: D
Solution :
[d] \[4Au(s)+8C{{N}^{-}}(aq)+2{{H}_{2}}O(aq)\xrightarrow{{{O}_{2}}}\] \[4{{[Au\underset{X}{\mathop{{{(CN)}_{2}}}}\,]}^{-}}+4O{{H}^{-}}(aq)\] \[2{{[Au{{(CN)}_{2}}]}^{-}}(aq)+Zn(s)\to \underset{Y}{\mathop{{{[Zn{{(CN)}_{2}}]}^{2-}}}}\,(aq)+2Au(s)\]
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