\[S{{O}_{2}}\] can be removed by using the following |
\[S{{O}_{2}}+2{{H}_{2}}S\to 2{{H}_{2}}O+3S\] |
\[S{{O}_{2}}+N{{a}_{2}}S{{O}_{3}}+{{H}_{2}}O\to 2NaHS{{O}_{3}}\] |
This is called |
A) synergistic process
B) non-regenerative process
C) desulphonation process
D) regenerative process
Correct Answer: D
Solution :
[d] \[S{{O}_{2}}\] content of the air can be removed by using |
\[{{H}_{2}}S\] gas which precipitates as sulphur |
\[2{{H}_{2}}S+{{O}_{2}}\to 2{{H}_{2}}O+3S\] |
\[N{{a}_{2}}S{{O}_{3}}\]which dissolves \[S{{O}_{2}}\] |
\[N{{a}_{2}}S{{O}_{3}}+{{H}_{2}}O+S{{O}_{2}}\to 2NaHS{{O}_{3}}\] |
You need to login to perform this action.
You will be redirected in
3 sec