A) \[\frac{\lambda q}{4\pi {{\varepsilon }_{0}}r}\]
B) \[\frac{\lambda q}{2\sqrt{2}\pi {{\varepsilon }_{0}}r}\]
C) \[\frac{2\sqrt{2}\lambda q}{\pi {{\varepsilon }_{0}}r}\]
D) \[\frac{4\lambda q}{\pi {{\varepsilon }_{0}}r}\]
Correct Answer: A
Solution :
[a] Net force \[{{F}_{net}}=q{{E}_{x}}\] \[F=q\frac{\lambda }{4\pi {{\varepsilon }_{0}}}=\frac{\lambda q}{4\pi {{\varepsilon }_{0}}r}\]You need to login to perform this action.
You will be redirected in
3 sec