A) \[N\]-type and its resistivity is 0.34 ohm-metre
B) \[P\]-type and its resistivity is 0.034 ohm-metre
C) \[N\]-type and its resistivity is 0.034 ohm-metre
D) \[P\]-type and its resistivity is 3.40 ohm-metre
Correct Answer: A
Solution :
[a] \[{{n}_{e}}=8\times {{10}^{18}}/{{m}^{3}},{{n}_{h}}=5\times {{10}^{18}}/{{m}^{3}}\] \[{{\mu }_{e}}=2.3\frac{{{m}^{2}}}{volt\text{-}\sec },{{\mu }_{h}}=0.01\frac{{{m}^{2}}}{volt\text{-}\sec }\] \[\because {{n}_{e}}>{{n}_{h}}\] so semiconductor is N-type Also conductivity \[\sigma =\frac{1}{\text{Resistivity}\,(\rho )}=e({{n}_{e}}{{\mu }_{e}}+{{n}_{h}}{{\mu }_{h}})\] \[\Rightarrow \frac{1}{\rho }=1.6\times {{10}^{-19}}[8\times {{10}^{18}}\times 2.3+5\times {{10}^{18}}\times 0.01]\] \[\Rightarrow \rho =0.34\,\Omega \text{-}m.\]
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