A) \[\frac{2}{3}G\]
B) \[2.5\,G\]
C) \[\frac{1}{3}G\]
D) \[\frac{5}{4}G\]
Correct Answer: A
Solution :
[a] \[{{A}_{v}}=\beta \frac{{{R}_{L}}}{{{R}_{l}}}\] \[\left( {{g}_{m}}=\frac{\Delta {{I}_{C}}}{\Delta {{V}_{B}}}=\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}{{R}_{l}}} \right)\] \[G=\left( \frac{\beta }{{{R}_{l}}} \right){{R}_{L}}\] \[\left( {{g}_{m}}=\frac{\beta }{{{R}_{l}}} \right)\] \[={{g}_{m}}{{R}_{L}}\Rightarrow G\propto {{g}_{m}}\] \[\frac{{{G}_{2}}}{{{G}_{1}}}=\frac{{{g}_{{{m}_{2}}}}}{{{g}_{{{m}_{1}}}}}\Rightarrow {{G}_{2}}=\frac{0.02}{0.03}\times G=\frac{2}{3}G\]
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