A) \[2\times {{10}^{4}}\]
B) \[2\times {{10}^{6}}\]
C) \[5\times {{10}^{4}}\]
D) \[5\times {{10}^{6}}\]
Correct Answer: A
Solution :
[a] 1 % of \[10GHz=10\times {{10}^{9}}\times \frac{1}{100}={{10}^{8}}Hz\] Number of channels\[=\frac{{{10}^{8}}}{5\times {{10}^{3}}}=2\times {{10}^{4}}\]
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