JEE Main & Advanced Mathematics Differential Equations Question Bank Mock Test - Differential Equations

  • question_answer
    The general solution of the equation \[\frac{dy}{dx}=1+xy\] is

    A) \[y=c{{e}^{-{{x}^{2}}/2}}\]

    B) \[y=c{{e}^{{{x}^{2}}/2}}\]

    C) \[y=(x+c){{e}^{-{{x}^{2}}/2}}\]

    D) None of these

    Correct Answer: D

    Solution :

    [d] \[\frac{dy}{dx}=1+xy\] Or \[\frac{dy}{dx}-xy=1\] I.F. \[={{e}^{\int{-xdx}}}={{e}^{-{{x}^{2}}/2}}\] Hence solutions is \[y.{{e}^{-{{x}^{2}}/2}}=\int{{{e}^{-{{x}^{2}}/2}}dx+c.}\] \[\int{{{e}^{-{{x}^{2/2}}}}dx}\] is not further integrable.


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