A) 1 : 2
B) 2 : 1
C) 4 : 1
D) 1 : 4
Correct Answer: C
Solution :
[c] Two wires carry the same current \[I={{n}_{1}}eA\,V{{d}_{1}}={{n}_{2}}eAV{{d}_{2}}\] So \[{{n}_{1}}V{{d}_{1}}={{n}_{2}}V{{d}_{2}}\] or \[\frac{V{{d}_{1}}}{V{{d}_{2}}}=\frac{{{n}_{1}}}{{{n}_{2}}}=4\Rightarrow V{{d}_{1}}:V{{d}_{2}}=4:1\]
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