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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Mock Test - Current Electricity

  • question_answer
    For a cell, a graph is plotted between the potential Difference V across the terminals of the cell and the current \[I\] drawn from the cell (see figure). The emf and the internal resistance of the cell are E and r respectively. Then

    A) \[E=2V,\,r=0.5\,\Omega \]

    B) \[E=2V,\,r=0.4\,\Omega \]

    C) \[E>2V,\,r=0.5\,\Omega \]         

    D) \[E>2V,\,r=0.4\,\Omega \]  

    Correct Answer: B

    Solution :

    [b] V=E-ir. When i=0, the potential reading is 2 V. hence emf is 2V. When V=0, i=5A. This gives \[r=0.4\Omega \]


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